(1/2)^-10-5x=4^2x

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Solution for (1/2)^-10-5x=4^2x equation: 



(1/2)^-10-5x=4^2x

We move all terms to the left:

(1/2)^-10-5x-(4^2x)=0

We add all the numbers together, and all the variables

-5x-4^2x-10+(+1/2)^=0

We multiply all the terms by the denominator


-5x*2)^-4^2x*2)^-10*2)^+(+1=0

Wy multiply elements

-40x^4=0

We do not support expression: x^4

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